### Program 7:Sum of N numbers

Program 7:

```#include<stdio.h>
main()
{
int i,n,sum=0;
printf("Enter a number\n");
scanf("%d",&n);
for(i=0;i<=n;i++)
{
sum=sum+i;
}
printf("%d\n",sum);
}```
Explanation:
1. First we initialized i,n, and sum which is declared as zero.
2. A number is given by user (say 5).
3. Now the logic is:sum=sum+i
• sum=0+0=0
• for next iteration i becomes '1' so sum=0+1=1
• for next iteration i becomes '2' so sum=2+1=3
• for next iteration i becomes '3' so sum=3+3=6
• for next iteration i becomes '4' so sum=4+6=10
• for next iteration i becomes '5' so sum=10+5=15
• for next iteration i becomes '6' which is not less than or equal to 'n'(i.e 5 as we took a value for explanation) then the loop terminates and goes to the next line.
4. Then the value of sum which is '15' will be printed.
Algorithm:-

1.Assign sum as 0
3.Assign i as 0
4.Repeat steps until i<=n
4.1)  sum=sum+i
4.2)  i=i+1
5.Print Sum
6.Stop

FlowChart:

Output:

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 Compiler Used by me C-Free 5.0(Recommended) Other Compilers Code Blocks(Recommended) Online Compilers Ideone(Remember to give input before executing online where ever necessary)