Program 403: Display All Palindromes and Non-Palindromes in a given sentence

Program 403: Display All Palindromes and Non-Palindromes in a given sentence

#include<stdio.h>
#include<string.h>
#include<ctype.h>
main()
{
    int i=0,j=0,k=0,l=0;
    char str1[100]={0},substr[100][100]={0},substr1[100][100]={0},substr2[100][100]={0},rev[100];
    printf("Enter a sentence\n");
    gets(str1);
    while(str1[k]!='\0')//for splitting sentence
    {
        j=0;
        while(str1[k]!=' '&&str1[k]!='\0')
        {
            substr[i][j]=str1[k];
            k++;
            j++;
        }
        substr[i][j]='\0';
        i++;
        if(str1[k]!='\0')
        {
            k++;
        }        
    }
    int len=i;
    k=0;
    l=0;
    for(i=0;i<len;i++)
    {
     strcpy(rev,substr[i]); 
     if(strcmp(strrev(rev),substr[i])==0)
     {
       strcpy(substr1[k],substr[i]);
       k++;
     }
     else
     {
      strcpy(substr2[l],substr[i]);
        l++;      
     }
    }
    if(k!=0)
    {
     printf("All Palindromes present in given Sentence\n");
     for(i=0;i<k;i++)
     {
       printf("%s\n",substr1[i]);
     } 
    }
    else
    {
     printf("No Palindromes Found\n");
    }
    if(l!=0)
    {
        printf("All Non Palindromes present in given Sentence\n");
        for(i=0;i<l;i++)
        {
            printf("%s\n",substr2[i]);
        } 
    }
    else
    {
      printf("No Non-Palindromes\n");
    }
    
  }

Explanation:
 //Coming Soon


Output: