### Program 290: Print Given Money or Value in Words

Program 290: Print Given Money or Value in Words

```#include<stdio.h>
main()
{
int i,j,k=0,value,count,a[10],dummy;
char *ones[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
char *temp[]={"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
char *tens[]={"-","-","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
//hundreds are same as ones
printf("Enter Value upto 6 digits to get in Words\n");
dummy=value;
scanf("%d",&value);
while(value>0)
{
i=value%10;
a[k]=i;
k++;
value/=10;
}
//Here if 12345 is given then a[0]=5,a[1]=4 and soon then last but one digit will be at a[1]
int totalDigits=k-1;
if(totalDigits<6)
{
for(i=totalDigits;i>=0;i--)
{
if(i==5 && a[i]!=0)
{
printf("%s lakh ",ones[a[i]]);
}
if(i==4 || i==3)
{
//Start
if(i==4 && a[i]==0)
{
printf("%s thousand ",ones[a[i-1]]);
i--;
}
else if(i==4 && a[i]==1)
{
printf("%s thousand ",temp[a[i-1]]);
i--;
}
else if(i==4)
{
printf("%s ",tens[a[i]]);
}
else
{
printf("%s thousand ",ones[a[i]]);
}
//end
}
if(i==2 && a[i]!=0)
{
printf("%s hundred and ",ones[a[i]]);
}
if(i==2 && a[i]==0)
{
printf("and ");
}
if(i==1 || i==0)
{
if(i==1 && a[i]==0)
{
printf("%s only\n",ones[a[i-1]]);
i--;
break;
}
if(i==1 && a[i]==1)
{
printf("%s only\n",temp[a[i-1]]);
i--;
break;
}
if(i==1 && a[i]!=1 && a[i]!=0)
{
printf("%s ",tens[a[i]]);
}
if(i==0 && a[i]!=0)
{
printf("%s only\n",ones[a[i]]);
}
}
}
}
else
{
printf("Enter only upto 6 digits\n");
}
}```
Explanation:

//Coming Soon

Output:

 Donate Buy me a coffee \$2.00 USD Buy me a burger \$5.00 USD Buy me a pizza \$10.00 USD
 Compiler Used by me C-Free 5.0(Recommended) Other Compilers Code Blocks(Recommended) Online Compilers Ideone(Remember to give input before executing online where ever necessary)