Program 290: Print Given Money or Value in Words
//Coming Soon
Output:
#include<stdio.h> main() { int i,j,k=0,value,count,a[10],dummy; char *ones[]={"zero","one","two","three","four","five","six","seven","eight","nine"}; char *temp[]={"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"}; char *tens[]={"-","-","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"}; //hundreds are same as ones printf("Enter Value upto 6 digits to get in Words\n"); dummy=value; scanf("%d",&value); while(value>0) { i=value%10; a[k]=i; k++; value/=10; } //Here if 12345 is given then a[0]=5,a[1]=4 and soon then last but one digit will be at a[1] int totalDigits=k-1; if(totalDigits<6) { for(i=totalDigits;i>=0;i--) { if(i==5 && a[i]!=0) { printf("%s lakh ",ones[a[i]]); } if(i==4 || i==3) { //Start if(i==4 && a[i]==0) { printf("%s thousand ",ones[a[i-1]]); i--; } else if(i==4 && a[i]==1) { printf("%s thousand ",temp[a[i-1]]); i--; } else if(i==4) { printf("%s ",tens[a[i]]); } else { printf("%s thousand ",ones[a[i]]); } //end } if(i==2 && a[i]!=0) { printf("%s hundred and ",ones[a[i]]); } if(i==2 && a[i]==0) { printf("and "); } if(i==1 || i==0) { if(i==1 && a[i]==0) { printf("%s only\n",ones[a[i-1]]); i--; break; } if(i==1 && a[i]==1) { printf("%s only\n",temp[a[i-1]]); i--; break; } if(i==1 && a[i]!=1 && a[i]!=0) { printf("%s ",tens[a[i]]); } if(i==0 && a[i]!=0) { printf("%s only\n",ones[a[i]]); } } } } else { printf("Enter only upto 6 digits\n"); } }Explanation:
//Coming Soon
Another option is to become a copywriter or copy editor where you're paid to write copies in an effort to promote products and services. Chris Harrold
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