 ### Program 49:Symbol Pattern 2

Program 49:

```#include<stdio.h>
main()
{
int i,j,num;
printf("Enter number of rows\n");
scanf("%d",&num);
for(i=1;i<=num;i++)
{
for(j=1;j<=i;j++)
{
printf("*");

}

printf("\n");
}
}
```
Explanation:

1. The program starts with initializing
• num → To store number of rows to be printed
• i,j Temporary variable.Where i is used for rows and j for columns
2. ```printf("Enter number of rows\n");
scanf("%d",&num);```
Taking number of rows from user
3. Main Logic goes here:
```for(i=1;i<=num;i++)
{
for(j=1;j<=i;j++)
{
printf("*");

}

printf("\n");
}```
4. As i=1.Lets take num=3 so we are going to print 3 rows
• Iteration 1: As i=1 and i<=num → 1<=3 which is true so iteration continues
• Sub Iterations:-
• ```for(j=1;j<=i;j++)
{
printf("*");

}```
• Sub Iteration 1:-j=1 and j<=i → 1<=1 which is true so sub iteration1 continues and prints '*' for 1 time
• Sub Iteration 2:- j=2 and j<=i → 2<=1 which is false so 2nd loop terminates for 1st iteration of 1st loop
• So till now '*' in the first row and first column is printed as shown in below screen shot
• Now 'i' will be incremented by 1 and now i=2.
• ` printf("\n");------->Will print next line so now the cursor will be in 2nd row`
• Iteration 2: As i=2 and i<=num → 2<=3 which is true so iteration continues.Now we are in 2nd row
• Sub Iterations:-
• ```for(j=1;j<=i;j++)
{
printf("*");

}```
• Sub Iteration 1:j=1 and j<=i → 1<=2 which is true so sub iteration1 continues and prints '*' for 1st time in the next row which is 2nd row and column 1
• Sub Iteration 2:j=2 and j<=i → 2<=2 which is true so sub iteration2 continues and prints '*' for 2nd time in the 2nd row and column 2
• Sub Iteration 3:j=3 and j<=i → 3<=2 which is flase so 2nd loop terminates for Iteration 2.
• So till now 2 rows are printed as shown
• Now 'i' will be incremented by 1 and now i=3.
• ` printf("\n");------->Will print next line so now the cursor will be in 3rd row`
• Iteration 3: As i=3 and i<=num → 3<=3 which is true so iteration continues.Now we are in 3rd row
• Sub Iterations:-
• ```for(j=1;j<=i;j++)
{
printf("*");

}```
• Sub Iteration 1:j=1 and j<=i → 1<=2 which is true so sub iteration1 continues and prints '*' for 1st time in the next row which is 3rd row and column 1
• Sub Iteration 2:j=2 and j<=i → 2<=2 which is true so sub iteration2 continues and prints '*' for 2nd time in the 3rd row and column 2
• Sub Iteration 3:j=2 and j<=i → 2<=2 which is true so sub iteration3 continues and prints '*' for 3rd time in the 3rd row and column 3
• Sub Iteration 4:j=3 and j<=i → 3<=2 which is flase 2nd loop terminates for Iteration 3.
• So till now 3 rows are printed as shown
• Now 'i' will be incremented by 1 and now i=4.
• ` printf("\n");------->Will print next line so now the cursor will be in 4th row`
• Iteration 4: As i=4 and i<=num → 4<=3 which is false so 1st loop will terminate and come out of loops.
• So our final out put for num=3 is given below

Output: 