Program 381: Find Angles of Triangle for given lengths of sides
//Coming Soon
Output:
#include<stdio.h>
#include<math.h>
main()
{
int a,b,c;
double A,B,C;
const double PI = 3.1415926;
printf("Enter length of a\n");
scanf("%d",&a);
printf("Enter length of b\n");
scanf("%d",&b);
printf("Enter length of c\n");
scanf("%d",&c);
/*
Reference:---
a² = b² + c² - 2bc cosA
b² = a² + c² - 2ac cosB
c² = b² + a² - 2ba cosC
*/
A=acos((-pow(a,2)+pow(b,2)+pow(c,2))/(2*b*c));
B=acos((pow(a,2)-pow(b,2)+pow(c,2))/(2*c*a));
C=acos((pow(a,2)+pow(b,2)-pow(c,2))/(2*a*b));
A*=180/PI;
B*=180/PI;
C*=180/PI;
printf("Angle of A=%lf\n",A);
printf("Angle of B=%lf\n",B);
printf("Angle of C=%lf\n",C);
}
Explanation://Coming Soon
Output:


