### Program 340 : Chakravyuha or Spiral Pattern Program(Question Taken from Codevitae(TCS) 2017)

Program 340 : Chakravyuha or Spiral Pattern Program(Question Taken from Codevitae(TCS) 2017)

```#include<stdio.h>
main()
{
int i,j,a[100][100],size,row=0,col=0,boundaryStart=0,boundaryEnd,num,evenRowCol=0,evenRow=0,evenCol=0,count=1;
printf("Enter number of rows\n");
scanf("%d",&size);
boundaryEnd=size-1;
for(i=0;i<size;i++)
{
for(j=0;j<size;j++)
a[i][j]=0;
}
while(count<=(size*size))
{
if(evenRowCol%2==0)
{
if(evenRow%2==0)
{
for(i=col;(i<=boundaryEnd) && (count<=size*size);i++){
a[row][i]=count;
count++;
}
evenRow++;
col=i-1;
row++;
}
else
{
for(i=col;(i>=boundaryStart) && (count<=size*size);i--)
{
a[row][i]=count;
count++;
}
evenRow++;
col=i+1;
row--;
boundaryStart++;
}
evenRowCol++;
}
else
{
if(evenCol%2==0)
{
for(i=row;(i<=boundaryEnd) && (count<=size*size);i++)
{
a[i][col]=count;
count++;
}
row=i-1;
col--;
evenCol++;
}
else
{
for(i=row;(i>=boundaryStart) && (count<=size*size);i--)
{
a[i][col]=count;
count++;
}
row=i+1;
col++;
evenCol++;
boundaryEnd--;
}

evenRowCol++;
}
}
for(i=0;i<size;i++)
{
for(j=0;j<size;j++)
printf("%3d ",a[i][j]);
printf("\n");
}
}
```
Explanation:

//Coming Soon

Output: