 ### Program 48:Symbol Pattern 1

Program 48:
```#include<stdio.h>
main()
{
int i,j,num;
printf("Enter number of rows\n");
scanf("%d",&num);
for(i=1;i<=num;i++)
{

for(j=1;j<=num;j++)
{
printf("*");

}

printf("\n");
}
}
```
Explanation:

1. The program starts with initializing
• num → To store number of rows
• i ,jTemporary variable
2. ```printf("Enter number of rows\n");
scanf("%d",&num);```
Taking number of rows from user.
3. Main Logic goes here:
```for(i=1;i<=num;i++)
{

for(j=1;j<=num;j++)
{
printf("*");

}

printf("\n");
}```
4. Lets take number of rows be 3.So num=3
• Iteration 1 of First Loop:i=1 and i<=3 which is true so 1st Loop execute
• Iteration 1 of 2nd Loop:j=1 and j<=3 which is true so iteration continues
• And prints '*' in 1st row and 1st coumn
• Now  will be incremented by 1
• So now j=2
• Iteration 2 of 2nd Loop:j=2 and j<=3 which is true so iteration continues
• And prints '*' in 1st row and 2nd coumn
• Now  will be incremented by 1
• So now j=3
• Iteration 3 of 2nd Loop:j=3 and j<=3 which is true so iteration continues
• And prints '*' in 1st row and 3rd coumn
• Now  will be incremented by 1
• So now j=4
• Iteration 4 of 2nd Loop:j=4 and j<=3 which is false so 2nd loop terminates
• So till now 1st row is printed
• Iteration 2 of First Loop:i=2 and i<=3 which is true so 1st Loop execute
• Iteration 1 of 2nd Loop:j=1 and j<=3 which is true so iteration continues
• And prints '*' in 2nd row and 1st coumn
• Now  will be incremented by 1
• So now j=2
• Iteration 2 of 2nd Loop:j=2 and j<=3 which is true so iteration continues
• And prints '*' in 2nd row and 2nd coumn
• Now  will be incremented by 1
• So now j=3
• Iteration 3 of 2nd Loop:j=3 and j<=3 which is true so iteration continues
• And prints '*' in 2nd row and 3rd coumn
• Now  will be incremented by 1
• So now j=4
• Iteration 4 of 2nd Loop:j=4 and j<=3 which is false so 2nd loop terminates
• So till now 1st row and 2nd row are printed
• Iteration 3 of 1st loop will also be same as above 2 iterations for 3rd row and finally all the 3 rows are printed as output
• Iteration 4 won't execute since i will be 4 and i<=3 i.e 4<=3 is not true

Output: 