 ### Program 35:Number Pyramid

Program 35:

```//       1
//      232
//     34543
//    4567654

#include<stdio.h>
main()
{
int i,j,left,right,k,rightcount,count,rows;
printf("Enter number of rows\n");
scanf("%d",&rows);
count=rows-1;
left=1;
right=0;

for(i=1;i<=rows;i++)
{//start of forloop
for(k=1;k<=count;k++)
{
printf(" ");
}
for(j=i;j<=left;j++)
{
printf("%d",j);
}
left+=2;
if(i!=1)
{
for(j=right;j>=i;j--)
{
printf("%d",j);
}

}
right+=2;
printf("\n");
count--;
}//end of forloop
}

```
Explanation:
1. The program starts with initializing
• rows → Taken from user to print those many rows
• i,j,k → used as variables.
• left,right → for printing left and right part of triangle.
• count → To controll spaces
2. ```printf("Enter number of rows\n");
scanf("%d",&rows);```
Taking number of rows as input from user
3. ```for(i=1;i<=rows;i++)
{```
For iterating number of row times
4. ```for(k=1;k<=count;k++)
{
printf(" ");
}```
To print spaces left side to achieve shape of pyramid.For example
__1
_232
34543
beside 1 we have two spaces and beside 2 we have one space and no space beside 3.this is for 3 rows.
5. ```for(j=i;j<=left;j++)
{
printf("%d",j);
}
left+=2;```
To print left part of triangle.left+=2 is for incrementing the left by 2 times for each iteration. As if you look at the outputin Iteration 1: 1 is printed and in iteration2: 2,3 are printed  and so on
6. ```if(i!=1)
{
for(j=right;j>=i;j--)
{
printf("%d",j);
}

}
right+=2;```
To print right part of triangle which is skipped if i==1as we dont want to print any thing to the right side of 1 in first row.  right+=2 is for incrementing right by 2 for each iteration.Unlike left right is initialized to 0 as right side printing will start with even number.
7. ```  printf("\n");
```
To start printing the numbers of pyramid in new line after finishing the iteration
8. count--  is used to decrement the number of spaces to be printed beside the row to achieve the shape of pyramid.If the pyramid is for 4 rows then in 1st row 3 spaces will be printed and in 2nd row 2 spaces will be printed and so on till the end.

Output:

#### 1 comment:

1. 3
2 3 2
1 2 3 2 1
Can anyone help me for this pattern?

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